流体ヒーター計算機

必要な電力を計算する

Calculate the power required in Kilowatts (Kw) to maintain water temperature using the flow rate in gallons or liters per minute (gpm or lpm) and temperature change required in degrees Centigrade (ºC) or Fahrenheit (ºF).

Formula Calculate Power Kw with Flow in GPM and Temperature in C

Flow Rate (GPM)

Temperature Change Required (ºC)

Enter values >0.

Formula Calculate Power Kw with Flow in LPM and Temperature in C

Flow Rate (LPM)

Temperature Change Required (ºC)

Enter values >0.

Formula Calculate Power Kw with Flow in GPM and Temperature in F

Flow Rate (GPM)

Temperature Change Required (ºF)

Enter values >0.

Formula Calculate Power Kw with Volume Temperature Time

Volume of water (Gal)

Temperature Change Required (ºC)

Time of Heating (Mins)

Enter values >0.

所要時間を計算する

Calculates the heating time in minutes (Mins) using the volume of water (Gal), the temperature change required in degrees Centigrade (ºC) or Fahrenheit (ºF), and the power available in Kilowatts (Kw).

Formula Calculate Time Minutes with Temperature C

Volume of Water (Gal)

Temperature Change Required (ºC)

Power Available (Kw)

Enter values >0.

Formula Calculate Time Minutes with Temperature F

Volume of Water (Gal)

Temperature Change Required (ºF)

Power Available (Kw)

Enter values >0.

必要な温度を計算する

Calculate the temperature change in degrees Centigrade (ºC) using the power available in Kilowatts (Kw), the heating time in minutes (Mins), and volume of water in gallons (Gal).

Formula Calculate Temperature Change in Degrees C

Power available (Kw)

Time of heating (Mins)

Volume of Water (Gal)

Enter values >0.

References & Definitions

H2O Properties

1 gallon = 231 in³ = 0.1337 ft³ = 3.785L

1 gallon = 8.337 lbs.

1 ft³ = 62.4 lbs. (at 20°C)

Specific heat = 1 calorie/gram-°C(at 15°C)

Specific heat = 1 BTU/lb.-°F (at 15°C)

Specific weight = 8.337 lbs./gallonheat of vaporization = 965 BTU/lb.

Abbreviations

KW = Killowatts

Gal = Gallons

In = Inches

Mins = Minutes

SpH = Specific Heat of Solution

SpW = Specific Weight of solution

ΔT°F = Change in degrees Fahrenheit

ΔT°C = Change in degrees Centigrade

Equivalents

1 in = 2.54 cm = 25.4 mm = 0.083ft

1 cm = 0.3937 in = 0.0328 ft.

1 in³= 16.39 cm³

1 BTU = 0.2933 watt-hrs

1 KW-Hr = 3412 BTU

Ohm’s Laws

Volts = Amperes x Ohms

Watts = (Amperes)² x Ohms

Amperes = Watts / Volts

Amperes/Phase =(Watts / Volts) x 0.578

(Assuming Balanced 3-Phase Load)